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27 September, 15:31

What is the equation of the circle with radius, r = 11, and the center at (0, - 7)

A. x ^ 2 + (y + 7) ^ 2 = 121

B. (x + 7) ^ 2 + y ^ 2 = 121

C. (x - 7) ^ 2 + y ^ 2 = 11

D. x ^ 2 + (y - 7) ^ 2 = 11

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Answers (1)
  1. 27 September, 18:42
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    A

    Step-by-step explanation:

    The equation of a circle in standard form is

    (x - h) ² + (y - k) ² = r²

    where (h, k) are the coordinates of the centre and r is the radius

    Given (h, k) = (0, - 7) and r = 11, then

    (x - 0) ² + (y - ( - 7)) ² = 11², that is

    x² + (y + 7) ² = 121 → A
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