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If Bradley has 4 times as many dimes as nickels and they have a combined value of 315 cents, how many of each coin does he have?

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  1. 8 November, 00:30
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    d=4n

    315=5n+10d

    315=5n+40n

    315=45n

    315/45=n

    7=n

    d=4n

    d=4 (7)

    d=28

    28 dimes and 7 nickels
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