F (x) = 2/x, g (x) = |x| - 1

What is the domain of (fog) (x) ?

will mark brainliest

x≠-1,1

Step-by-step explanation:

f (g (x)) is a composition where g (x) is is substituted for x in f (x).

Recall, f (x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.

|x|-1=0

|x|=1

x=1,-1