Coram is at basketball practice preparing to shoot free throws. The probability of Coram making a free throw is 77%. What is the probability that he makes his first free throw on the second shot? A. 79% B. 95% C. 88% D. 83% I think the answer is C

Answer: The answer is 17.71%.

Step-by-step explanation: Given that Coram is preparing to shoot free throws at basketball practice.

The probability that Coram will make a free throw = 77% = 0.77.

So, the probability of Coram miss the throw = 1 - 0.77 = 0.23.

Therefore, the probability that he makes his first throw on the second shot

= probability of missing the throw in first shot * probability of making a throw

= 0.23 * 0.77

=0.1771

17.71%.

Thus, the required probability is 17.71%.