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11 January, 15:45

What is the perimiter of ABC with vertices A (-2,9), B (7-3), and c (-2,-3) in the coordinate plane?

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  1. 11 January, 16:08
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    |AB| = √ ((7 - (-2)) ^2 + (-3 - 9) ^2) = 15

    |BC| = √ ((-2 - 7) ^2 + (-3 - (-3)) ^2) = 9

    |AC| = √ ((-2 - (-2)) ^2 + (-3 - 9) ^2) = 12

    Perimeter = 15 + 9 + 12 = 36
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