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11 January, 23:25

Scorpion Gulch Shelter is having a pumpkin sale for Halloween. The pumpkins will be displayed on a triangular region in the parking lot, with sides 45 ft, 75 ft, and 102 ft. Each pumpkin takes about 3 ft^2 of space.

(a) About how many pumpkins can the shelter display?

(b) Find the measure of the middle-sized angle.

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  1. 12 January, 03:13
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    A) 513 pumpkin

    B) Ø = 42.2 degree

    Step-by-step explanation:

    Given that the triangle are of sides 45 ft, 75 ft, and 102 ft.

    Let's first calculate the semi perimeter s of the triangle

    S = (a + b + c) / 2

    S = (45 + 75 + 102) / 2

    S = 222/2 = 111

    Area = sqrt root (s (s-a) (s-b) (s-c))

    Area = sqrt root (111 (66) (36) (9))

    Area = 1540.66 square feet

    If each pumpkin takes about 3 ft^2 of space.

    The shelter display 1540.66 / 3 = 513.55

    513 pumpkin

    The measure of the middle-sized angle can be obtained by using cosine formula

    75^2 = 45^2+102^2-2 (45) (102) cosØ

    5625 = 12429 - 9180cosØ

    9180cosØ = 12429 - 5625

    CosØ = 0.74118

    Ø = 42.2 degree
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