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18 May, 16:14

What are the solutions of the system of equations for x + y = 2 and y = - 1/4 x^2 + 3

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  1. 18 May, 17:04
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    Use substitution

    from first equation: y = 2 - x

    Substitute in the 2nd equation:-

    2 - x = - 1/4x^2 + 3

    -1/4 x^2 + x + 1 = 0

    solving this gives x = - 0.83, 4.83

    Giving y = 2 - - 0.83 = 2.83, 2 - 4.83 = - 2.83

    Answer (-0.83, 2.83) and (4.83, - 2.83)
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