Find the zeroes of f (x) = 2x^2+32

first step)

with the equation + -b-√b∧2-4ac/2a you can find the zeros of the equation

second step)

for b = 0, a = 2, c = 32

+ - 0-√o∧2-4 (2) (32) / 2*2 = √-256 / 4, as you can see it, it is a negative number inside the root, and this equation do not have zeros, therefore it do not have solution