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17 December, 21:09

40:14

The longest side of an obtuse triangle measures 20 cm. The two shorter sides measure x em and 3x cm.

Rounded to the nearest tenth, what is the greatest possible value of x?

LE

6,3

6.4

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  1. 17 December, 23:54
    0
    x LE 6.3.

    Step-by-step explanation:

    For an obtuse triangle

    c^2 > a^2 + b^2 where c is the longest side. So:

    20^2 > x^2 + (3x) ^2

    400 > 10x^2

    x^2 < 40

    x < 6.324

    x < 6.3.
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