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13 January, 09:53

A shopkeeper blends3 types of tea A, B, C in a ratio 6:4:7. if the mass ofv tea C in the mixture is 28kg find the difference in the mass of other 2 of teas

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  1. 13 January, 10:19
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    The answer to the question is 8kg
  2. 13 January, 13:37
    0
    A would be 6/7 x 28kg = 24 kg B would be 4/7 x 28kg = 16 kg so the difference of the masses is 24 - 16 = 8kg
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