In ∆ABC, AC = 15 centimeters, m∠B = 68°, and m∠C = 24°. What is BC to two decimal places?

In ∆ABC, AC = 15 centimeters, m B = 68°, and m C = 24°. What is BC to two decimal places?

Answer provided by our tutors

we are given two angles and one side (which is not between the angles)

we find the angle m A by using 'angles of a triangle add to 180°':

m A = 180 - (m B + m C)

m A = 88°

we can find side BC by using The Law of Sines:

BC/sin A = AC/sin B

BC/sin 88° = 15 / sin 68°

BC = 15*sin 88° / sin 68°

BC = 16.19 cm.