In the rhombus m 1=18x m 2=x+y and m 3=30z. Find the value of x+y+z

A Rhombus has four equal straight sides. We can assume that the rhombus in this problem is square-shaped with 90° angles.

m1 = 18x; 90 = 18x; 90/18 = x; 5 = x

m2 = x + y; 90 = 5 + y; 90 - 5 = y; 85 = y

m3 = 30z; 90 = 30z; 90/30 = z; 3 = z

x = 5; y = 85; z = 3

x + y + z ⇒ 5 + 85 + 3 = 93