Ask Question
25 September, 18:34

A concession stand is selling hot dogs and hamburgers during a game. at halftime they sold a total of 78 hot dogs and hamburgers and brought in $105.50. how many of each item did they sell if hamburgers sold for $1.50 and hot dogs sold for $1.25?

+4
Answers (1)
  1. 25 September, 20:30
    0
    Let x=number of hamburgers sold and y=number of hot dogs sold.

    Step 1)

    cost of burgers X # of burgers + cost of hotdogs X # of hotdogs=$ collected 1.5x + 1.25y=105.5

    step 2)

    # of burgers sold + number of hot dogs sold = total number of items sold

    x + y = 78

    step 3) solve for y in the second equation

    y = 78 - x

    step 4) substitute y = 78 - x in the first equation for the value of y and solve for x

    1.5x + 1.25 (78 - x) = 105.50

    1.5 x + 97.5 - 1.25x=105.50

    .25x = 8

    x = 32

    step 5) plug in our value for x in the second equation and solve for y

    x+y=78

    32+y=78

    y=46

    answer 32 hamburgers and 46 hot dogs
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A concession stand is selling hot dogs and hamburgers during a game. at halftime they sold a total of 78 hot dogs and hamburgers and ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers