Ask Question
27 January, 06:05

The length and width of a rectangle lot are in the ratio 3 to 2. if he perimeter of the lot is 530yards, find the length and width

+5
Answers (1)
  1. 27 January, 07:22
    0
    Length = l = 3x

    Width = w = 2x

    P = 2l + 2w

    P = 2 (3x) + 2 (2x)

    530 = 6x + 4x

    530 = 10x

    53 = x

    Length = 3x = 3 (53) = 318 / 2 sides = 159

    Width = 2x = 2 (53) = 212 / 2 sides = 106

    the length of the lot is 159 yards

    the width of the lot is 106 yards
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The length and width of a rectangle lot are in the ratio 3 to 2. if he perimeter of the lot is 530yards, find the length and width ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers