After 1 second the ball is 76 feet in the air: after 2 seconds it is 144 feet in the air. Find the height of the function. h (x) = ?

General equation for height, h

h = ut + 0.5gt^2

at t=1s, h = 76 feet

76 = u*1 + 0.5*a*1^2

76 = u + 0.5a

at t=2s, h = 144 feet

144 = u*2 + 0.5*a*2^2

144 = 2u + 2a

72 = u + a

Subtract 2 equations

0.5a = - 4

a = - 8

u = 80

So the equation,

h (x) = 80t + 0.5 * (-8) t^2

h (x) = 80t - 4t^2