Five times the sum of three consecutive integers is 150. What are the integers

5 (x + (x+1) + (x+2)) = 150

5 (3x+3) = 150

15x+15=150

15x=135

x=9

Your three consecutive integers are 9, 10, and 11.

Let x=1st integer

x+1=2nd integer

x+2=3rd integer

5 (x+x+1+x+2) = 150

5 (3x+3) = 150

15x+15=150

15x=135

x=9

So you put what x is

1st integer (x) = 9

Since it's three consecutive integers, you add one to the 2nd integer

2nd integer (x+1) = 10

Then you do the same thing for the third integer

3rd integer (x+2) = 11