7x+3/x2-8x+15+3x/x-5=1/3-x

Combine like terms

(3/x^2) + 7x - 8x + 15 + 3x/x - 5 = (1/3) - x

The x will cancel out of 3x/x term leaving just x. Move all x's to left of equal sign and all constants to the right.

(3/x^2) + 7x-8x+x = - 15-3+5 + (1/3)

(3/x^2) = - 13 + (1/3)

Convert - 13 to a fraction - - 39/3 and add to 1/3

(3/x^2) = - 38/3

Multiply both sides by x^2.

3 = (-38/3) x^2

Multiply both sides by (-3/38)

(-9/38) = x^2

Take square root of both sides

Sq rt (-9/38) = x

Bring an i out from under the sq rt to get rid of the negative sign.

3i / (sq rt 38) = x

Multiply top and bottom by sq rt 38 to get it off the denominator.

3i (sq rt 38) / 38 = x