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28 August, 06:06

Given cosθ=5/6 and θ lies in Quadrant I.

What is the exact value of sinθ in simplified form?

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  1. 28 August, 07:50
    0
    With this, we know cos=x/r

    x = 5

    and

    r = 6

    We need to find y.

    25 + y² = 36

    y² = 11

    y = √11

    sin of theta would be √11/6
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