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3 February, 14:29

Solving system by substitution x=3y+11, 2x-3y=16

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Answers (2)
  1. 3 February, 16:02
    0
    1. You plug the x equation in the nest on. 2 (3y+11) - 3y=16.

    2. You then simplify it. 6y+22-3y=16

    3. You simplify it more. 3y+22=16.

    4. Next you subtract 22 from each side. 3y=-6.

    5. Divide both sides by 3. y=-2

    6. Then substitute y for the first equation. x=3 (-2) + 11

    7. Next you simplify. x=-6+11

    8. Simplify more. x=5

    9. You get your results. x=5 and y=-2
  2. 3 February, 17:23
    0
    Input 3y+11 for x

    2 (3y+11) - 3y=16

    6y+22-3y=16

    3y = - 6

    Divide by 3 to isolate y

    y=-2

    Now for x ...

    x=3 (-2) + 11

    =-6+11

    =5

    x=5

    Coordinates (5,-2)
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