How do i get the solution to graph 2x+3y=12

2x + 3y = 12

I am going to put this in y = mx + b form, where m is ur slope and b is ur y intercept.

2x + 3y = 12

3y = - 2x + 12

y = - 2/3x + 4 ... slope is - 2/3 and y int is (0,4)

x int can be found by subbing in 0 for y and solving for x

2x + 3y = 12

2x + 3 (0) = 12

2x = 12

x = 6 ... so x int is (6,0)

start at y int (0,4) ... and since the slope is - 2/3, come down 2 spaces, and to the right 3 spaces, then down 2 spaces, to the right 3 spaces ... keep doing that and u should cross the x axis at (6,0)