Find sin2z, cos2x and tan2x if cosx = (3/5) and x is in quadrant 1

cos (x) = ³/₅

cos⁻¹[cos (x) ] = cos⁻¹ (³/₅)

x ≈ 53.13

sin (2x) = sin[2 (53.13) ]

sin (2x) = sin (106.26)

sin (2x) = 0.960001

cos (2x) = cos[2 (53.13) ]

cos (2x) = cos (106.26)

cos (2x) = - 0.27999657

tan (2x) = tan[2 (53.13) ]

tan (2x) = tan (106.26)

tan (2x) = - 3.428617001