Find the measure of ∠D if

∠A =

5

2

x + 16

∠B =

7

2

x + 20

∠C =

3

2

x + 68

∠D =

3

2

x + 40

Question

Mathematics

King Potter

19 March, 12:45

Find the measure of ∠D if

∠A =

5

2

x + 16

∠B =

7

2

x + 20

∠C =

3

2

x + 68

∠D =

3

2

x + 40

+3

Answers (1)

Know the Answer?

German Francis · Answer 1

Sum of all Angles of a quadrilateral=360

Ang. A + Ang. B + Ang. C + Ang. D = 360

=> (52x + 16) + (72x + 20)

+ (32x + 68) + (32x + 40) = 360

=> 188x = 216

> x = 1.1489

Ang. D=32 X 1.1489 + 40 = 76.7648

Find the measure of ∠D if∠A =52x + 16∠B =72x + 20∠C =32x + 68∠D =32x + 40

Find the measure of ∠D if

∠A =

5

2

x + 16

∠B =

7

2

x + 20

∠C =

3

2

x + 68

∠D =

3

2

x + 40