Identify the vertex of the parabola with the quadratic equation u = 6x squared - 72x + 220

Don't report what you don't understand

the x value of the vertex of the parabola in form

y=ax^2+bx+c

is - b/2a

given

y=6x^2-72x+220

x value of vertex is - (-72) / (2*6) = 72/12=6

xvalue is 6

sub that for x in the equation

y=6 (6) ^2-72 (6) + 220

y=216-432+220

y=4

(x, y)

vertex is (6,4)