Bianca has many jelly beans in a jar. Chris has 12 less than bianca, Ruby has 5 jelly beans less than chris Mario has 6 jelly beans less than ruby. If Mario has 11 beans, how many does Bianca have?

Bianca's beans = Chris' + 12

Chris' beans = Bianca's - 12 OR Ruby's + 5

Ruby's beans = Chris' - 5 OR Mario's + 6

Mario's beans = Ruby's - 6

Mario = 11 beans

Ruby = 17 beans

Chris = 22 beans

Bianca = 34 beans

B=biancha number of beans

c=chris number of beans

r=ruby number of beans

m=mario number of beans

c=b-12

r=c-5

m=r-6

m=11

so subsitute and solve

m=11

11=r-6

add 6 to both sides

17=r

subsitute

17=c-5

add 5 to both sides

22=c

subsitute

22=b-12

add 12 to both sides

34=b

biancha=34