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7 February, 06:00

Which equations can be used to solve for y, the length of the room? Check all that apply. y (y + 5) = 750 y2 - 5y = 750 750 - y (y - 5) = 0 y (y - 5) + 750 = 0 (y + 25) (y - 30) = 0

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  1. 7 February, 08:08
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    Let's assume length of the room as y

    so the width of the room = y - 5

    Area

    y * (y - 5) = 750
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