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27 June, 23:47

How do I show work for 5 - (a-4) = 3 (a+2)

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  1. 28 June, 02:54
    0
    Here is how I would show the work for this problem

    5 - (a-4) = 3 (a+2)

    5-a+4 = 3*a+3*2

    5-a+4 = 3a+6

    -a+9 = 3a+6

    -a+9+a = 3a+6+a

    9 = 4a+6

    9-6 = 4a+6-6

    3 = 4a

    4a = 3

    4a/4 = 3/4

    a = 3/4

    So the solution is the fraction a = 3/4 (in decimal form 0.75)

    Let me know if you have any questions or issues with any of the steps shown above. It's a lot to take in so feel free to ask about anything really.
  2. 28 June, 03:16
    0
    5 - (a-4) = 3 + (a+2)

    distribute invible - 1

    5-a+4=4+a+1

    9-a=a+5

    add a to both sides

    9=2a+5

    minus 5 both sides

    4=2a

    divide by 2 both sides

    2=a
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