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15 April, 14:51

4sin (x) - 4=0

solve for x

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  1. 15 April, 16:17
    0
    First let's isolate the sin (x) term

    4sin (x) - 4 = 0

    4sin (x) = 4

    sin (x) = 1

    Now use the unit circle and you'll see that the only solution in the interval [0,2pi) is x = pi/2

    If you want to ignore the restriction and consider all solutions, then x = (pi/2) + 2pi*n where n is any integer
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