What are the vertex focus and directrix of the parabola with the given equation

y=1/28 (x-4) ^2-5

If the parabola is rotated so that its vertex is (h, k) and its axis of symmetry is parallel to the y-axis, it has an equation of (x - h) ^2 = 4p (y - k), where the focus is (h, k+p) and the directrix is y = k - p. So, we need to determine the values from the equation.

y=1/28 (x-4) ^2-5

(x-4) ^2 = 28 (y+5)

(h, k) = (4, - 5)

p = 7

focus = (h, k+p) = 4,2

directrix = y = k - p = - 12

Hope this answers the question.