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5 August, 19:10

Two promotional stands are to be placed in an ellipse-shaped room-one at each foci-and are 3 units from the center. If the room is 8 units wide, what is its length?

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  1. 5 August, 21:13
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    We are given the value of a and c; a is the width of the ellipse and c is the focus of the ellipse. For an ellipse the equation to be used to find b or the length of the ellipse is:

    a^2 = b^2 + c^2

    substitute the values in the equation to solve for the missing variable:

    8 units is 2a, therefore, a = 4

    4^2 = b^2 + 3^2

    solve for b:

    b = √7 units

    Therefore, the value of b is √7 units. To solve for the length of the ellipse (2b), multiply b with 2:

    2b = √7 * 2

    Length = 2√7 units
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