Using the AC method Ax^2 + Bx+C

How do I solve this problem? and check the answer back into equation? Mark as brainlest on my list!

25x^2 - 20x + 4

25=5*5=1*25

4=2*2=1*4

Factor to get sum of-20

(5x-2) (5x-2)

solve 5x-2=0=>x=2/5 is root of multiplicity 2 for both functions.

So

find ac

list all products that equal ac

find the ones that add to b

rewrite

factor

undistribute

so

25x^2-20x+4

ac=4*25=100

what 2 numbers, when multipied together, results in 100 but adds to - 20?, I did this in previous quesiton, the answer is - 10 and - 10

25x^2-10x-10x+4

(25x^2-10x) + (-10x+4)

(5x) (5x-2) + (-2) (5x-2)

factor out (5x-2)

(5x-2) (5x-2)

well, there is no equal sign, but we will assume it equals 0

(5x-2) ^2=0

5x-2=0

5x=2

x=2/5