Use factoring to solve the following quadratic: 6x2 + 23x - 18 = 0

6x²+23x-18=0

(3x-2) (2x+9) = 0

Therefore, x=2/3, and x = (-9) / 2

6x^2+23x-18=0 - - 6*-18=-108 factors that made 23 are 27 and - 4

So,

6x^2+27x-4x-18=0 - - factorise each half of the equation i. e. 6x^2+27x and 4x-18

3x (2x+9) - 2 (2x+9) - - the brackets are the same, that's one side, and combine the 2 other terms outside the brackets for the second bracket.

(3x-2) (2x+9) = 0

3x-2=0

3x=2

x=2/3

2x+9=0

2x=-9

x=-9/2

x=2/3 or x=-9/2 - - there we go, fixed.