Find the area of a triangle when a=22 degree, b=105 degree, and b=14 30.4 units^2 32.1 units^2 31.2 units^2 34.8 units^2

C = 180 - (22 + 105) = 180 - 127 = 53 degrees

Area of triangle = 1/2 ab sin C

But a / sin A = b / sin B or a = b sin A / sin B = (14 x sin 22) / sin 105 = 5.429

Therefore, Area of triangle = 1/2 x 5.429 x 14 x sin 53 = 30.4 units^2