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5 February, 16:07

Write the first trigonometric function in terms of the second for θ in the given quadrant ... sec θ, sin θ; θ in quadrant I

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  1. 5 February, 16:32
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    We have sec = 1/cos

    Then we also have cos^2 = 1 - sin^2

    Also we have cos = sqrt (1 - sin^2)

    Substitute the derived cosine function to sec then we have

    Sec = 1 / (sqrt (1-sin^2)
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