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3 November, 22:59

The water level in a plastic pool changed by - 8gallons each hour due to a small hole in the bottom. After 6 hours, the pool contained 132 gallons. How much water was in the pool originally?

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  1. 3 November, 23:08
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    You can find this using the equation x = 132 + (8) (6), where x is how much water was in the pool originally.

    x = 132 + (8) (6) Multiply

    x = 132 + 48 Add

    x = 180

    There were originally 180 gallons of water in the pool.
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