Ask Question
11 July, 17:56

Each day, Steve walked 1/12 mile more than the previous day. The first day he walked 1/12, the second day he walked 2/12 mile, the third day he walked 3/12 mile. On which day did the sum of his walks total at least 1 complete mule?

+2
Answers (1)
  1. 11 July, 18:39
    0
    1st day = 1/12

    2nd day = 2/12

    3rd day = 3/12

    4th day = 4/12

    5th day = 5/12

    6th day would be = 6/12

    If it continues in that order, the sum of the walks would total 1 mile when:

    They all add up to 12/12

    Add = 1/12 + 2/12 + 3/12 + 4/12 = 10/12

    That is still not up to 12/12

    So we add up the 5th day also = 10/12 + 5/12 = 15/12 = 1 3/12 miles

    So on the 5th day the sum of his walks total at least 1 completed mile.

    At least 1 means 1 and above. As you can see the answer we got 1 3/12 is already more than 1.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Each day, Steve walked 1/12 mile more than the previous day. The first day he walked 1/12, the second day he walked 2/12 mile, the third ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers