An airplane has an air speed of 520 mph with a heading of 215 degrees. Find the plane's ground speed and course if it encounters the following winds.

A.) A headwind of 32 mph.

B.) A tailwind of 32 mph.

Assuming east is positive x, north is positive y, break down the airplane's velocity into a vector in the x-y plane.

The plane is traveling 340 mph at a bearing of 210 degrees or (340cos (210), 340 sin (210)).

The wind is blowing from the west (to the east) at 50 mph or (50,0).

The actual ground speed would be the vector sum of those two (340 cos (210) + 50, 340 sin (210)) or (-294.4+50,-170) or (-244.4,-170).

The magnitude of that velocity vector is

For direction

Since this angle is measured from the (-y) axis, we add 180 to get the actual heading.

The plane is traveling at 297.8 mph at a heading of 214.8 degrees.