Ask Question
21 July, 01:46

Hot Air Balloon 1 is 10 meters above the ground, rising 15 meters per minute, and Hot Air Balloon 2 is 150 meters above the ground descending 20 meters per minute.

In how many minutes will the balloons be at the same height?

How high will the balloons be at that time?

(Let x represent the time and y represent the height)

+4
Answers (1)
  1. 21 July, 03:13
    0
    You have two equations

    y = 10 + 15x and y = 150 - 20x

    since y = y you can get

    10 + 15x = 150 - 20x now we solve for x

    +20x + 20x add 20x to both sides

    10 + 35x = 150 now subtract 10 from both sides

    -10 - 10

    35x = 140 then divide both sides by 35

    /35 / 35

    so x = 4 minutes

    to find what high they are at 4 minutes

    plug 4 back into the equation for x

    y = 10 + 15 (4) = 10 + 60 = 70

    so 70 meters from the ground
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Hot Air Balloon 1 is 10 meters above the ground, rising 15 meters per minute, and Hot Air Balloon 2 is 150 meters above the ground ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers