Jayden and Sheridan both tried to find the missing side of the right triangle. Jayden's Work Sheridan's Work a2 + b2 = c2 a2 + b2 = c2 72 + 132 = c2 72 + b2 = 132 49 + 169 = c2 49 + b2 = 169 218 = c2 b2 = 120 14.76 ≈ c b ≈ 10.95 Is either of them correct? Explain your reasoning.

Question

Mathematics

Parker Pearson

11 April, 06:20

Jayden and Sheridan both tried to find the missing side of the right triangle. Jayden's Work Sheridan's Work a2 + b2 = c2 a2 + b2 = c2 72 + 132 = c2 72 + b2 = 132 49 + 169 = c2 49 + b2 = 169 218 = c2 b2 = 120 14.76 ≈ c b ≈ 10.95 Is either of them correct? Explain your reasoning.

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Braylon Carlson · Answer 1

No, they are both incorrect by my understanding of your question use the Pythagorean theorem a^2 + b^2 = c^, therefore, 7^2 + x^2 = 13^2 or 49+x=169 then solve normally 169-49=120 √120 = 5

The answer is 5