Simplify the function f (t) = sinh (ln (t)). Then, find the derivative of your simplified form of f (t).

We first consult the hyperbolic definition of sinh t. The expression is equal to (e^t - e^-t) / 2. since there is ln t inside, the appropriate equivalent should be (e^ln t - e^ - ln t) / 2. This is equal to (t + t) / 2 equal to t. The differential is equal to 1.