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30 November, 04:06

F (x) = 6x^2 + 6x + 12 (Solve by factoring.)

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  1. 30 November, 05:46
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    You can't solve for the zeros by factoring because the function is not factorable.

    I'll show you what happens:

    f (x) = 6x^2 + 6x + 12

    To solve for the zeros (when f (x) = 0), set f (x) equal to 0.

    0 = 6x^2 + 6x + 12

    First you can factor out a 6.

    0 = 6 (x^2 + x + 2)

    Divide by 6.

    0 = x^2 + x + 2

    Now you need two integers that add up to the coefficient of x (1) and multiply to the product of the last term and the coefficient of x^2. This number is 2.

    No two integers add up to 1 and multiply to 2.
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