Find the measure of ∠B if ∠A = 5 2 x + 40 ∠B = 7 2 x + 20 ∠C = 3 2 x + 20 ∠D = 3 2 x + 40

Question

Mathematics

Domino

13 May, 03:03

Find the measure of ∠B if ∠A = 5 2 x + 40 ∠B = 7 2 x + 20 ∠C = 3 2 x + 20 ∠D = 3 2 x + 40

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Answers (1)

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Brenden Kelley · Answer 1

In a quadrilateral

∠A = 52 x + 40

∠B = 72 x + 20

∠C = 32 x + 20

∠D = 32 x + 40

∠A + ∠B + ∠C + ∠D = 360° = 52x+40+72x+20+32x+20+32x+40

= 188x + 120

188x + 120 = 360°

188x = 240°

x = 240/188 = 1.27°

∠B = 72x+20 = (72*1.27) + 20 = 111.44°