Which function has real zeros at x = - 10 and x = - 6? f (x) = x2 16x 60 f (x) = x2 - 16x 60 f (x) = x2 4x 60 f (x) = x2 - 4x 60

Would assume the function is a quadratic function. It is degree 2.

The zeros or roots are x = - 10, and x = - 6.

For quadratic:

x² - (sum of roots) x + product = 0

x² - (-10 + - 6) x + (-10) * (-6) = 0

x² - (-16) x + (60) = 0

x² + 16x + 60 = 0

f (x) = x² + 16x + 60