A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 9% vinegar, and the second brand contains 14% vinegar. The chef wants to make 249 mL of a dressing that is 13% vinegar. How much of each should he use?

Question

Mathematics

Jovanni

29 January, 07:41

A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 9% vinegar, and the second brand contains 14% vinegar. The chef wants to make 249 mL of a dressing that is 13% vinegar. How much of each should he use?

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Answers (1)

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Kaleigh · Answer 1

First brand = A, second brand = B.

A + B = 249ml

9% A + 14% B = 13% 249ml

B = 249ml - A

9% A + 14% (249ml - A) = 13% 249ml

9A + 14 (249ml - A) = 13 * 249ml

9A + 3486ml - 14A = 3237ml

5A = 249ml

A = 49,8ml

B = 249ml - A = 199,2ml

Answer: He should use 49,8ml of first brand and 199,2ml of second brand.

Also note: That's an approximation, because the volumes are not strictly additive. For example: mixing 50ml pure ethanol with 50ml water will give you about 95ml of mixture. To get an accurate answer, you'd have to measure the volume of the final mixture and then divide your total alcohol content by that.