Find the equation of the circle in standard form for the given center (h, k) and radius r: (h, k) = (5, 4), r = 2

(x - 5) 2 + (y - 4) 2 = 4

(x + 5) 2 + (y + 4) 2 = 2

(x + 5) 2 + (y + 4) 2 = 4

(x - 5) 2 + (y - 4) 2 = 2

Question

Mathematics

Isai

28 December, 11:52

Find the equation of the circle in standard form for the given center (h, k) and radius r: (h, k) = (5, 4), r = 2

(x - 5) 2 + (y - 4) 2 = 4

(x + 5) 2 + (y + 4) 2 = 2

(x + 5) 2 + (y + 4) 2 = 4

(x - 5) 2 + (y - 4) 2 = 2

+5

Answers (1)

Know the Answer?

Chelsea Barron · Answer 1

If cente ris (h, k) and radius is r then

equatn is (x-h) ^2 + (y-k) ^2=r^2

so

center (5,4)

r=2

h=5

k=4

(x-5) ^2 + (y-4) ^2=2^2

(x-5) ^2 + (y-4) ^2=4

first option

Find the equation of the circle in standard form for the given center (h, k) and radius r: (h, k) = (5, 4), r = 2(x - 5) 2 + (y - 4) 2 = 4(x + 5) 2 + (y + 4) 2 = 2(x + 5) 2 + (y + 4) 2 = 4(x - 5) 2 + (y - 4) 2 = 2

Find the equation of the circle in standard form for the given center (h, k) and radius r: (h, k) = (5, 4), r = 2

(x - 5) 2 + (y - 4) 2 = 4

(x + 5) 2 + (y + 4) 2 = 2

(x + 5) 2 + (y + 4) 2 = 4

(x - 5) 2 + (y - 4) 2 = 2