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16 April, 22:13

What is the derivative of sin sin sin x

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  1. 17 April, 01:12
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    Sin [sin (sinx) ]

    You have two ways into this the first is:

    sin y

    where y = sinz and z = sinx

    d (siny) / dx = cosy * dy/dx

    dy/dx = cosz * dz/dx

    dz/dz = cosx

    and do reverse sub

    dy/dz = cosz * cosx

    d (siny) / dx = cosz * cosx * cosy = cos (sin (sinx)) * cosx * cos (sinx)

    or the way I prefer is take the derivative of each term in row:

    cos (sin (sinx)) * cos (sinx) * cosx
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