The sum of 6 consecutive integers is 393. What is the third number in this sequence?

So, let first be x

then, second be x+1

and so on ...

so the eqn will be,

x+x+1+x+2+x+3+x+4+x+5=393

6x = 393-15

x = 378/6

x = 63

so first no I 63

second will be 64

and third (your answer) will be 65!

X + x+1 + x+2 + x+3 + x+4 + x+5 = 393

Therefore, 6x+15=393

6x = 378

Thus, x = 63.

So the first is 63, the second is 64, the third is 65, fourth is 66, fifth is 67, and six is 68.

63 + 64 + 65 + 66 + 67 + 68 = 393

65 is the third number in this sequence.