An object is thrown in the air with an initial velocity of 5 m/s from a height of 9 m. The equation h (t) = - 4.9t2 + 5t + 9 models the height of the object in meters after t seconds. About how many seconds does it take for the object to hit the ground? Round your answer to the nearest hundredth of a second.

Question 11 options:

0.94 seconds

1.50 seconds

2.00 seconds

9.00 seconds

Question

Mathematics

Jacoby

10 November, 21:11

An object is thrown in the air with an initial velocity of 5 m/s from a height of 9 m. The equation h (t) = - 4.9t2 + 5t + 9 models the height of the object in meters after t seconds. About how many seconds does it take for the object to hit the ground? Round your answer to the nearest hundredth of a second.

Question 11 options:

0.94 seconds

1.50 seconds

2.00 seconds

9.00 seconds

+4

Answers (1)

Know the Answer?

Danny Ayala · Answer 1

After being thrown, the object would take about 2 seconds to hit the ground. We can find this by looking at the second x-intercept, which is where the graphed equation crosses the line on the right.