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23 January, 17:34

Solving a system of linear equations using the substitution method.

5x+4y=-26

5-x=-6y

+5
Answers (2)
  1. 23 January, 19:42
    0
    Solve for x in 2nd equation

    times - 1 both sides

    x-5=6y

    add 5

    x=6y+5

    sub

    5 (6y+5) + 4y=-26

    30y+25+4y=-26

    34y+25=-26

    minus 25 both sides

    34y=-51

    divide both sides by 34

    y=-3/2

    sub back

    x=6y+5

    x=6 (-3/2) + 5

    x=-18/2+5

    x=-9+5

    x=-4

    (-4,-3/2) is solution
  2. 23 January, 21:18
    0
    We write x in terms of y in order to substitute using the second equation

    -x=-6y-5

    x = 6y+5

    We substitute what we got above in the first equation

    5 (6y+5) + 4y=-26

    We solve for y

    30y+25+4y=-26

    34y+25=-26

    34y=-51

    y=-51/34

    Then we plug what we got for y back in our first equation in order to get the value of x as well

    x=6 (-51/34) + 5

    x=-4

    So the solutions are:

    x=-4

    y=-1.5
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