The area of square B is 25% greater than the area of square A. If the area of square B is 80 square inches, then what is the length in inches of the perimeter of square A?

Best Answer: Ab = 1.25Aa

80 = 1.25Aa

Aa = 64

Aa = Sa^2

64 = Sa^2

Sa = 8

Pa = 4S

Pa = 4 (8)

Pa = 32

D

Area Square B = area Square A * 1.25

80 / 1.25 = area Square A

area Square A = 64

area of a square = side^2

side of a square = sq root (area)

side of square A = 8

So each side of square A = 8

perimeter of a square = 4 * side

perimeter of square A = 32