What is the equation for a circle with center (2, - 3) and radius of 6?

Question 5 options:

(x + 2) 2 + (y + 3) 2 = 36

(x - 2) 2 + (y + 3) 2 = 6

(x - 2) 2 + (y + 3) 2 = 36

(x - 2) 2 + (y - 3) 2 = 36

The general formula for a circle is:

x^2 + y^2 = r^2

Since the r^2 = 36, we know the first two options are incorrect

If the circle's centre is at (2, - 3), the numbers being squared should be the negative of the coordinate

So, the final answer is (x-2) ^2 + (y+3) ^2 = 36